69x^2+121x+10=0

Solution for 69x^2+121x+10=0 equation:

69x^2+121x+10=0

a = 69; b = 121; c = +10;
Δ = b2-4ac
Δ = 1212-4·69·10
Δ = 11881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11881}=109$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(121)-109}{2*69}=\frac{-230}{138}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(121)+109}{2*69}=\frac{-12}{138}
=-2/23
$